s^2+7s+4=0

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Solution for s^2+7s+4=0 equation: 



s^2+7s+4=0

a = 1; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·1·4
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{33}}{2*1}=\frac{-7-\sqrt{33}}{2}
$


$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{33}}{2*1}=\frac{-7+\sqrt{33}}{2}
$

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